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Volume of Gases and Number of Moles

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Question

What volume of water is to be added to 100 cm³ of 0.5 N sulphuric acid to prepare a decinormal solution ?

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Solution

$A c c o r d i n g t o v o l u m e t r i c p r i n c i p l e V_{1} N_{1} = V_{2} N_{2} V_{1} \times 0.1 = 100 \times 0.5 (d e c i n o r m a l m e a n s 1 / 10 N) V_{1} = \frac{100 \times 0.5}{0.1} = 500 m l T h a t m e a n s 500 - 100 = 400 c m^{3} o f w a t e r m u s t b e a d d e d t o 100 c m^{3} s u l p h u r i c a c i d s o a s t h e p r e p a r e t h e r e q u i r e d c o n c e n t r a t i o n .$

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