Question

What volume of water should be added to 50 ml of HNO3 having density 1.5 g/ml and 63 percentage by weight to have one molar solution

Answer 1

Dear Student

The mass of HNO₃ solution :
$$\begin{gathered} =density\times volume \\ =1.5\times 50 \\ =75g \end{gathered}$$
Now as 63 % by weight HNO₃ is present in 75 g of solution , so the mass of HNO₃ will be :
$$\begin{gathered} =\frac{63}{100}\times 75 \\ =47.25g \end{gathered}$$
Now number of mole of HNO₃ :
$$\begin{gathered} =\frac{47.25}{63} \\ =0.75mol \end{gathered}$$
So, to make the 1 molar solution total of the water must present in the solution will be = 750 ml.

Regards