What volume strength of 100 mL H2O2 is required for the complete reaction with 15.8 g of KMnO4 in basic medium? (Molar mass of KMnO4 is 158 g/mol).
A
5.6
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B
11.2
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C
1.86
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D
3.73
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Solution
The correct option is A 5.6 15.8 g of KMnO4 = 0.1molKMnO4 Since n-factor of KMnO4 in basic medium is 1, thus 0.1molKMnO4=0.1eqv.ofKMnO4 Therefore, H2O2 required is 0.1 eqv. So, volume strength =5.6×N ⇒5.6×0.1100×1000=5.6