What volumes of $12 N H C l$ and $3 N H C l$ must be mixed to form one litre $6 N H C l$ ?

Open in App

Solution

Let $x m L$ of $12 N H C l$ and $y m L$ of $3 N H C l$ be mixed to form one litre $6 N H C l$ .
So, $x + y = 1000 . . . . (i)$
Applying the formula $N_{1} V_{1} + N_{2} V_{2} = N_{3} V_{3}$
$N_{1} = 12 N, V_{1} = x, N_{2} = 3 N, V_{2} = y, N_{3} = 6 N, V_{3} = 1000$
So, $12 x + 3 y = 6 \times 1000 . . . . (i i)$
Putting the value of $y = (1000 - x)$ from eq. (i) in eq. (ii),
$12 x + 3 (1000 - x) = 6000$
or $12 x - 3 x + 3000 = 6000$
or $9 x = 3000$
$x = \frac{3000}{9} = 333.3 m L$
So, $y = (1000 - x) = (1000 - 333.3) = 666.7 m L$ .
i.e., $333.3 m L 12 N H C l$ and $666.7 m L 3 N H C l$ are mixed.

Suggest Corrections

Similar questions

18.9

H N O_{3}

3.2

N a O H

1

18.9

H N O_{3}

1

3.2

(1 : 3.75)

C H_{3} C O O H + C_{2} H_{5} O H \Leftrightarrow C H_{3} C O O C_{2} H_{5} + H_{2} O

Join BYJU'S Learning Program