What volumes of nitrogen and hydrogen are required to produce 20 cc of ammonia gas at S.T.P.?

10cc, 30cc

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10cc, 20cc

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20cc, 30cc

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15cc, 30cc

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Solution

The correct option is A 10cc, 30cc
$N_{2} + 3 H_{2} \to 2 N H_{3}$

Volume of $N_{2}$ required $= \frac{1}{2} \times 20 = 10 c c$

Volume of $H_{2}$ required $= \frac{3}{2} \times 20 = 30 c c$

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Similar questions

Q. Nitrogen reacts with hydrogen to give ammonia. Calculate the volume of the ammonia gas formed when nitrogen reacts with 6 litres of hydrogen. All volumes measured at S.T.P.

Q. How many grams of hydrogen gas is required to produce 4.8 mol of ammonia on a reaction with an excess of nitrogen?

1.nitrogen reacts with hydrogen to give ammonia.Calculate the volume of the ammonia gas formed when nitrogen reacts with 6 liters of hydrogen.All gases measures at s.t.p ,using Gay lussacs law ,with step by step process

N_{2} (g) + 3 H_{2} (g) \to 2 {N H}_{3} (g) + 92

According to the equation above, what mass of nitrogen gas is required to produce

68

g of ammonia?

Q. How many moles of nitrogen (

N_{2}

) are required to produce 10 moles of ammonia (

{NH}_{3}

) by reaction with hydrogen (

H_{2}

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What volumes of nitrogen and hydrogen are required to produce 20 cc of ammonia gas at S.T.P.?

The correct option is A 10cc, 30ccN2+3H2→2NH3Volume of N2 required=12×20=10 ccVolume of H2 required=32×20=30 cc

The correct option is A 10cc, 30cc
$N_{2} + 3 H_{2} \to 2 N H_{3}$

Volume of $N_{2}$ required $= \frac{1}{2} \times 20 = 10 c c$

Volume of $H_{2}$ required $= \frac{3}{2} \times 20 = 30 c c$