Question

What was the day of the week on 15th August, 1947?

Answer 1

15th August, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)
Odd days in 1600 years = 0
Odd days in 300 years = (5 $\times$ 3)=15=1
46 years = (11 leap years + 35 ordinary years)
= (11$\times$ 2 +35 $\times$ 1) odd days = 57 odd days
=(8 weeks + 1 day) = 1 odd day.
$\therefore$ Odd days in 1946 years = (0+1+1) = 2.
Jan.Feb.March April May June July Aug.
(31+28+31+30+31+30+31+15)=227 days.
227 days=(32 weeks + 3 days) = 3 odd days.
Total number of odd days = (2+3) = 5.
Hence, the required day is Friday.