Question

What was the day of the week on 17^thJune, 1998?

• A. Monday
• B. Tuesday
• C. Wednesday
• D. Thursday

Answer 1

The correct option is C

Wednesday

${17}^{th}$ June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 $\times$ 3) ≡ 1

97 years have 24 leap years + 73 ordinary years.

Number of odd days in 97 years (24 $\times$ 2 + 73) = 121 = 2 odd days.

Jan. Feb. March April May June

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

$\therefore$ 168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.