Question

What was the day of the week on 26${}^{th}$ June, 1997?

• A. Monday
• B. Tuesday
• C. Wednesday
• D. Thursday
• E. Sunday

Answer 1

The correct option is D

Thursday

26${}^{th}$ June, 1997 = (1996 years + Period from 1.1.1997 to 26.6.1997)

Odd days in 1600 years = 0

Odd days in 300 years = ${}^{\circ }$ 1

96 years has 24 leap years + 72 ordinary years

Number of odd days on 96 years = (24 $\times$ 2 + 72) = 120 = 1 odd day

Jan + Feb + March + April + May+ June

(31 + 28 + 31 + 30 + 31 + 26) = 177 days = 25 weeks = 2 odd days

Total number of odd days = (0 + 1 + 1 + 2) = 4 }

Given day is Thursday.