What weight of copper will be deposited by passing 2 faradays of electricity through a cupric salt?

2.0

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3.175

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63.5

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127.0

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Solution

The correct option is C $63.5$
2F electricity implies 2 moles of electrons exchanged.

${C u}^{2 +} + 2 e^{-} \to C u$
1 mole of Cu is formed from 2 moles of electrons.

Thus, weight of Cu $= 1 \times 63.5 = 63.5 g$

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Similar questions

2

C u = 63.5 g / m o l

What weight of copper will be deposited by passing 2 faradays of electricity

through a cupric salt (Atomic weight of Cu = 63.5)

[NCERT 1975; CPMT 1977, 79]

C u S O_{4}

C u = 63.5

C u S O_{4}

C u S O_{4}

C u

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