Question

What weight of sodium hydroxide is required to neutralise $100ml$ of $0.1N$ $HCl$?

• A. $4g$
• B. $0.4g$
• C. $0.04g$
• D. $40g$

Answer 1

Answer: (B)

$0.4g$

$NaOH+HCl\to NaCl+H_{2}O$

$1$ mole of $HCl$ is neutralized by $1$ mole ($40$ g) of $NaOH$.

$100$ ml of $0.1N$ $HCl$ corresponds to $0.01$ moles.

Thus, $0.01$ mole of $HCl$ is neutralized by $0.01$ mole (or $0.4$ g) of $NaOH$.

Thus, the correct option is $B$