Question

What weight of sodium hydroxide is required to neutralize 100ml of 0.1N HCl

Answer 1

Sodium Hydroxide is NaOH. Same gram equivalent will be required.

Gram equivalent = w/E = N×V.

Here w is the weight of compound(NaOH), E is the equivalent weight of compound(NaOH), N is normality of solution and V is the volume of solution in litres.

So if we take 100 ml of 0.1N HCl, then gram equivalent = N×V = 100 ×0.1/1000 = 0.01

Now we calculate gram equivalent of NaOH which will be equal to 0.01

So, 0.01 = w/40 (equivalent weight of NaOH is 40).

From here we have w= 0.4 gram

So 0.4 gram of NaOH is required to neutralize 100 ml of 0.1N HCl.