What weight of sulfur is present in 47.5 g ${CS}_{2}$

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Solution

Step 1: Calculating the percentage sulphur present in one mole of ${CS}_{2}$
The molecular mass of ${CS}_{2}$ = Mass of C + 2 x Mass of S = 12 + 2 x 32 = 76 u
Let us calculate the percentage of the weight of sulfur in ${CS}_{2}$
$Percentage of Sulphur = \frac{weight of sulphur}{weight of {CS}_{2}} x 100 Percentage of Sulphur = \frac{64}{76} x 100 Percentage of Sulphur = 84.2 %$
Step 2: Calculating the mass of sulphur in 47.5 g ${CS}_{2}$
$Weight of sulphur = Weight of {CS}_{2} x Percentage of weight of Sulphur Weight of sulphur = 47.5 x 84.2 % Weight of sulphur = 47.5 x \frac{84.2}{100} Weight of sulphur = 39.99 g$
Hence 39.99g weight of sulphur is present in 47.5 g of ${CS}_{2}$ .

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What weight of sulfur is present in 47.5 g CS2

What weight of sulfur is present in 47.5 g ${CS}_{2}$