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Question

# What will be a, b and c for the following reaction to be balanced? aFeCl3+bMgO→cFe2O3+dMgCl2

A

a = 2, b = 3, c = 3, d = 4

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B

a = 2, b = 4, c = 3, d = 3

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C

a = 1, b = 32, c = 12, d = 2

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D

a = 1, b = 32, c = 12, d = 32

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Solution

## The correct option is D a = 1, b = 32, c = 12, d = 32 aFeCl3+bMgO→cFe2O3+dMgCl2 Now, for iron we will equate the number of atoms on the reactant and product sides: a = 2c Chlorine: 3a = 2d Magnesium: b = d Oxygen: b = 3c Now we take a = 1 and put this in a = 2c which gives C = 12 and from 3a = 2d we will get D = 32 and from b = d we get b = 32 So, the balanced equation is: FeCl3 + 32MgO→ 12Fe2O3 + 32MgCl2

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