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Question

What will be a, b and c for the following reaction to be balanced?

aFeCl3+bMgOcFe2O3+dMgCl2



A

a = 2, b = 3, c = 3, d = 4

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B

a = 2, b = 4, c = 3, d = 3

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C

a = 1, b =  32, c = 12, d = 2

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D

a = 1, b =  32, c = 12, d =  32

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Solution

The correct option is D

a = 1, b =  32, c = 12, d =  32


aFeCl3+bMgOcFe2O3+dMgCl2

Now, for iron we will equate the number of atoms on the reactant and product sides:  a = 2c

Chlorine: 3a = 2d

Magnesium: b = d

Oxygen: b = 3c

Now we take a = 1 and put this in a = 2c which gives C = 12 and from 3a = 2d we will get D = 32 and from b = d we get b =  32

So, the balanced equation is:
FeCl3 + 32MgO 12Fe2O3 + 32MgCl2


Chemistry

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