What will be at the tens place of a number obtained by multiplying 13 with 31?
A
4
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B
3
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C
1
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D
0
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Solution
The correct option is D 0 Let’s split 31 and 13.
31 = 30 + 1
13 = 10 + 3
Multiplying each of these four numbers with the other, we can fill in the table.
Adding the numbers, we have,
Therefore, the number at the tens place is 0.