Question

What will be critical angle for the material of refractive index $\sqrt{2}$ ?

Answer 1

If C is critical angle, then

sinC=$\frac{1}{n}$, where n is refractive index of the material.

Now, n =$\sqrt{2}$, therefore ,

sinC=$\frac{1}{\sqrt{2}}$ Then, C =45${}^{\circ }$