Question

What will be de-Broglie wavelength of an electron moving with a velocity of $1.2\times {10}^{5}m{s}^{-1}$

• A. 6.068 X 10^-9
• B. 3.133 X 10^-37
• C. 6.626 X 10^-9
• D. 6.018 X 10^-7

Answer 1

The correct option is C

6.626 X 10^-9

$\lambda =\frac{h}{p},p=mv$

$\lambda =\frac{h}{mv}=\frac{6.62\times {10}^{-34}}{9.1\times {10}^{-31}\times 1.2\times {10}^5}$

$\lambda =6.626\times {10}^{-9}m$