What will be shape factor $F_{21}$ for two very long plates arranged in following figure? Point y is just above the center of plate (1)

0.314

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Can't be determined

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0.707

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0.718

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Solution

The correct option is D $0.718$
Joint the point y with point X.

$F_{12} = \frac{A_{1} + A_{2} - A_{3}}{2 A_{1}}$

For a unit length

$A_{1} = 0.250 \times 1 = 0.25 m^{2}$

$A_{2} = A_{3} = 0.160 m$

$F_{12} = \frac{0.25 + 0.16 - 0.16}{2 \times 0.25} = 0.5$

$A_{1} F_{12} = A_{2} F_{21}$

$0.25 \times 0.5 = 0.16 F_{21}$

$F_{21} = 0.78125$

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