What will be the amount of heat evolved by burning 10L of methane under standard conditions?
(Given heats of formation of CH4,CO2andH2Oare−76.2,−398.8and−241.6kJmol−1 respectively)
A
805.8kJ
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B
398.8kJ
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C
359.7kJ
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D
640.4kJ
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Solution
The correct option is C359.7kJ Equation, CH4+2O2→CO2+2H2O ΔH=HP(Product)−HR(Reactant) ΔH∘f(CO2)+2ΔH∘f(H2O)−(ΔH∘f(CH4)+2ΔH∘f(O2)) =−398.8−2×241.6−(−76.2+2×0)=−805.8kJmol−1 22.4LofCH4( 1 mole) gives 805.8kJ 10LofCH4 will give 805.822.4×10=359.73kJ
Hence, Option C is correct.