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Question

What will be the amount of heat evolved by burning 10L of methane under standard conditions?
(Given heats of formation of CH4,CO2 and H2O are 76.2,398.8 and 241.6 kJmol1 respectively)

A
805.8 kJ
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B
398.8 kJ
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C
359.7 kJ
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D
640.4 kJ
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Solution

The correct option is C 359.7 kJ
Equation,
CH4+2O2CO2+2H2O
ΔH=HP(Product)HR(Reactant)
ΔHf(CO2)+2ΔHf(H2O)(ΔHf(CH4)+2ΔHf(O2))
=398.82×241.6(76.2+2×0)=805.8 kJ mol1
22.4 L of CH4( 1 mole) gives 805.8 kJ
10 L of CH4 will give 805.822.4×10=359.73 kJ
Hence, Option C is correct.

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