What will be the angle of diffracting for the first minimum due to Fraunhoffer diffraction with sources of light of wave length 550 nm and slit of width 0.55 mm.

0.001 red

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0.01 red

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1 red

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0.1 red

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Solution

The correct option is B 0.001 red
Using $d sin θ = n λ, F o r n = 1$
$sin θ = \frac{λ}{d} = \frac{550 \times 10^{- 9}}{0.55 \times 10^{- 3}} = 10^{- 3} = 0.001 r a d$

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What will be the angle of diffracting for the first minimum due to Fraunhoffer diffraction with sources of light of wave length 550 nm and slit of width 0.55 mm.

The correct option is B 0.001 redUsing dsinθ=nλ, For n=1sinθ=λd=550×10−90.55×10−3=10−3=0.001 rad

The correct option is B 0.001 red
Using $d sin θ = n λ, F o r n = 1$
$sin θ = \frac{λ}{d} = \frac{550 \times 10^{- 9}}{0.55 \times 10^{- 3}} = 10^{- 3} = 0.001 r a d$