Question

What will be the angle of elevation of top of a 15 m high tower at a point 15 m away from the base of the tower?

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Given: Height of the tower (AB) = 15 m
Horizontal distance from the tower (BC) = 15 m

$tan\theta =\frac{AB}{BC}=\frac{15}{15}=1$
$\Rightarrow \theta ={45}^{\circ }$