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Raoult's Law

what will be ...

Question

what will be the area of an object on which the force of 200N acts to produce a pressure of 600pa?

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Solution

Dear Student,
$W e k n o w t h a t P = \frac{F}{A} s o 600 = \frac{200}{A} A = \frac{200}{600} = 1 / 3 m^{2}$
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