What will be the bond order of the species with electronic configuration $1 s^{2} 2 s^{2} 2 p^{5}$ ?

One

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Two

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Three

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Zero

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Solution

The correct option is A One
Formula to calculate bond order:-
$\frac{N u m b e r o f e l e c t r o n s i n B M O - N u m b e r o f e l e c t r o n s i n A B M O}{2}$
fill the electrons and we will get $1$ bond order with $9$ electrons.
So the correct option is [A].

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H N O_{2}

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