Question

What will be the change in hybridization from $H_{2}O$ to $H_3{O}^{+}$ ?

• A. $s{p}^2$ to $s{p}^3$
• B. $s{p}^3$ to $s{p}^2$
• C. $s{p}^{3}d$ to $s{p}^3$
• D. both have same hybridisation

Answer 1

The correct option is D both have same hybridisation

Steric Number $\left(x\right)$ = $\frac{1}{2}\left(M+V-C+A\right)$.
where, M = number of monovalent surrounding atoms
V = number of valence electrons on the central atom
C = charge (with sign)
A=charge on anion
$H_{2}O$
$\text{Steric Number (x)}=\frac{1}{2}(6+2-0+0)$.
$\text{Steric Number (x)}=4$.
Hybridisation =$s{p}^3$

$H_3{O}^{+}$
$\text{Steric Number (x)}=\frac{1}{2}(6+3-1+0)$.
$\text{Steric Number (x)}=4$.
Hybridisation =$s{p}^3$