What will be the correct order of $S N_{2}$ / $E_{2}$ ratio for the %yield of the product of the following halide?
a) III > IV > II > I
b) III > II > IV > I
c) I > III > IV > II
d) II > I > III > IV

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Solution

Answer: a
Explanation: Least hindered halide give fastest $S N_{2}$ reaction as the hindrance increases. As the hindrance increases, the occurrence of $S N_{2}$ reaction decreases.

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