Question

What will be the cost of making a closed cone of tin sheet having radius of base 6 m and slant height 8 m if the rate of making is
Rs.10 per sq.m ?

Answer 1

Radius of the base of cone, r = 6 m

Slant height of the cone, l = 8 m

∴ Total surface area of the cone = $\mathrm{\pi }$r(r + l) = $\frac{22}{7}\times 6\times \left(6+8\right)=\frac{22}{7}\times 6\times 14$ = 264 m²

Rate of making the cone of tin sheet = Rs 10/m²

∴ Total cost of making the cone of tin sheet

= Total surface area of the cone × Rate of making the cone of tin sheet

= 264 × 10

= Rs 2640

Thus, the cost of making the cone of tin sheet is Rs 2640.