Question

What will be the Coulomb force between the two pieces after the transfer of electrons if they are 10 cm apart? (Avogadro's number is $6\times {10}^{23}mo{l}^{-1}$.)

Answer 1

Number of atoms in 10 g of copper is

$n=\frac{10}{63.5}\times 6\times {10}^{23}=9.448\times {10}^{22}$

Number of electrons transferred is

$N=\frac{n\times 1}{1000}=9.448\times {10}^{19}$

$F=\frac{k{q}^2}{r^2}=\frac{9\times {10}^9\times (15.12{)}^2}{(0.10{)}^2}=2.05\times {10}^{14}N$