Question

What will be the current flowing through the $6K\Omega$ resistor in the circuit shown, where the breakdown voltage of the zener is $6$V?

• A. $\frac{2}{3}$mA
• B. $1$mA
• C. $10$mA
• D. $\frac{3}{2}$mA

Answer 1

Answer: (A)

$\frac{2}{3}$mA

$\because$ Zener break done $=6$V
Sp potential across $4K\Omega =6$V
and potential across $6K\Omega =(10-6)=4$V
Current through the $6K\Omega =\frac{4}{6000}A\Rightarrow \frac{2}{3000}A=\frac{2}{3}$mA.