What will be the depression in freezing point of a $0.5 m$ $K C l$ solution? The molal freezing point constant of water is ${1.86}^{o} C m^{- 1}$ .

- {1.86}^{o} C

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- {0.372}^{o} C

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- {3.2}^{o} C

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0^{o} C

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Solution

The correct option is B $- {1.86}^{o} C$
We have,

$Δ T_{f} = i K_{f} m$

[Note: $i = 2$ for $K C l$ ]

$Δ T_{f} = 2 \times 1.86 \times 0.5 = 1.86$

The freezing point of KCl solution $= (0 - 1.86)^{0} C = - {1.86}^{0} C$

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{1.86}^{o} C

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(Molal depression constant of water = 1.86 C^{o} k g m o l^{- 1})

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