What will be the displacementcurrent for a fully charged capacitor?

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Solution

Dear Student,

$Electric flux through plates of capacitor, φ_{E} = \frac{q}{ε_{0}} Here, q = constant, the capacitor is fully charged . Displacement current, I_{D} = ε_{0} \frac{{dφ}_{E}}{dt} I_{D} = ε_{0} \frac{d (\frac{q}{ε_{0}})}{dt} = 0$

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What will be the displacementcurrent for a fully charged capacitor?

Dear Student, Electric flux through plates of capacitor, φE=qε0Here, q=constant, the capacitor is fully charged.Displacement current, ID=ε0dφEdtID=ε0dqε0dt=0 Regards

Dear Student,

$Electric flux through plates of capacitor, φ_{E} = \frac{q}{ε_{0}} Here, q = constant, the capacitor is fully charged . Displacement current, I_{D} = ε_{0} \frac{{dφ}_{E}}{dt} I_{D} = ε_{0} \frac{d (\frac{q}{ε_{0}})}{dt} = 0$

Regards