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Question
What will be the divisibility rule of 2,3,5,6,4,8,9,11,12,15,25.
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Solution
Divisible byIfExamples:2The last digit is even (0,2,4,6,8)128 is 129 is not3The sum of the digits is divisible by 3381(3+8+1=12,and 12÷3=4)Yes 217(2+1+7=10, and 10÷3=313)No4The last 2 digits are divisible by 41312 is (12÷4=3)7019 is not5The last digit is 0 or 5175 is 809 is not6The number is divisible by both 2 and 3114(it is even,and1+1+4=6 and 6÷3=2)Yes 308(it is even,but 3+0+8=11 and 11÷3=323)No7If you double the last digit and subtract it form the rest of the number and the answer is:672(Double2 is 4,67−4=63 and 63÷7=9)Yes 0,or divisible by 7905(Double5 is 10,90−10=80,and 80÷7=1137)No (Note: you can apply this rule to that answer again if you want) 8The last three digits are divisible by 8109816(816÷8=102)Yes 216302(302÷8=3734)No9The sum of the digits is divisible by 91629(1+6+2+9=18 and again,1+8=9)Yes (Note: you can apply this rule to that answer again if you want)2013(2+0+1+3=6)No10The number ends in 0220 is 221 is not11Add and subtract digits in an alternating pattern(add first,subtract second,add third,etc)Then the answer must be913(9−1+3=11)Yes. 0 or3729(3−7+2−9=−11)Yes divisible by 113729(3−7+2−9=−11)Yes987(9−8+7=8) No12The number is divisible by both 3 and 4648(By3?6+4+8=18 and 18÷3=6Yes.By4?48÷4=12 Yes)Yes 524(By3?5+2+4=11,11÷3=323 No.Don′t need to check by 4.) No.
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