wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What will be the E0 value for the given half cell reaction?
Cr2+(aq)+2eCr(s)
Given:
E0 value for the half cell reaction,
Cr3+(aq)+eCr2+(aq); E0=0.41 V
Cr3+(aq)+3eCr(s); E0=0.74 V

A
+0.33 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.15 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.33 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.91 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 0.91 V
ΔG0=nFE0

Cr3+(aq)+3eCr(s)....(1); ΔG01=+3F×0.74
Cr3+(aq)+eCr2+(aq)......(2); ΔG02=+F×0.41
Reversing equation (2), we get,
Cr2+(aq)Cr3+(aq)+e.....(3); ΔG03=F×0.41

Adding equation (1) and (3), we get,
Cr2+(aq)+2eCr(s).....(4); ΔG04=2F×E0

ΔG04=ΔG01+ΔG03
2F×E0=+3F×0.74F×0.41
2×E0=3×0.74+0.41
E0=3×0.74+0.412
E0=1.812
E0=0.91 V

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constant from Nernst Equation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon