Given,
irms=20 A
Frequency f=75 Hz
Peak current, io=irms√2=20√2A
i=iosin(ωt)
i=iosin(2πft)
i=20√2sin(2π×75t)
i=20√2sin(150πt)
Therefore, the correct equation for the AC current will be 20√2 sin(150πt).