CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What will be the equation of tangent at the point P(10,8) on the rectangular hyperbola x236y236=1?

A
5x+4y=18
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5x4y=18
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8x5y=18
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4x5y=18
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 5x4y=18
Given: Rectangular hyperbola x236y236=1; Point P(10,8)

To Find: Equation of tangent

We know that the equation of tangent at P(x1,y1) on rectangular hyperbola is: xx1yy1=a2

From the given data, we have a2=36,x1=10,y1=8

Substituting all the values in the equation of tangent.

10x8y=36

5x4y=18

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Jupiter
Watch in App
Join BYJU'S Learning Program
CrossIcon