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Potassium Dichromate

What will be ...

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What will be the equilibrium concentration at 127C if equilibrium constant at 27C is 4 for Habbers process (Enthalpy change H = -46.06 kJ)

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Q. What will be the equilibrium constant at

127^{0} C

if equilibrium constant at

27^{0} C

is 4 for reaction

N_{2}

+

3 H_{2}

⇌

2 N H_{3}

△ H

Q. What will be the equilibrium constant at

127^{o}

C. If equilibrium constant at

27^{o}

4

N_{2} + 3 H_{2} ⇌ 2 N H_{3}; Δ H = - 46.06

Q. What will be the equilibrium constant at

127

. If equilibrium constant at

27

4

N_{2} + {3 H}_{2} ⇌ {2 N H}_{3}

Δ H = - 46.06 k J

Q. A reaction is at equilibrium at

153^{o} C

and the enthalpy change for the reaction is

42.6 k J m o l^{- 1} .

What will be the value of

△ S

Q. The enthalpy change for a reaction at equilibrium is

- 20.5

^{- 1}

. Then the entropy change for this equilibrium at 410 K is:

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