What will be the final product of the given reaction?
$C H_{3} - C - (C H_{3})_{2} - O H + 2 K \to$

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Solution

When alkali metals react with alcohols they remove proton from alcohols to convert them in hydrogen gas.
$C H_{3} - C - (C H_{3})_{2} - O H + 2 K ⟶ C H_{3} - C - (C H_{3})_{2} - - O K + \frac{1}{2} H_{2}$

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