Question

What will be the force in member GE in the truss shown below.

• A. 400 N
• B. 600 N
• C. 800 N
• D. None of these

Answer 1

The correct option is C 800 N


$\sum F_x=0$
$A_x=400N$
$\sum M_D=0$
$(A_y\times 12)+(400\times 3)=1200\times 4$
$A_y=300N$
Using method of section

$\sum M_c=0$
$F_{GE}\times 3=A_y\times 8$
$F_{GE}=\frac{8}{3}\times 300$
$F_{GE}=800N$