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Question

What will be the geometry and shape of NH2-

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Solution

ep for NH2=(V+L+AC)2=(5+2+1)2 =4

(central atom N, valence 5)

4 ep Tetrahedral

Now,

ep = 4 & Ligands = 2 bp = 2 & lp = 2

Now, the geometry will be tetrahedral but there will be & lone pairs attached to it.

Because of lone pairs, the angle also decreases.

So, it will be having v - shape [Because while deciding shape. Lone pairs are not considered]


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