wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

What will be the H+ ion concentration of a solution prepared by mixing 50 mL of 0.20 M NaCl, 25 mL of 0.10 M NaOH and 25 mL of 0.30 M HCl?

A
0.5 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.05 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.02 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.10 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.05 M
NaCl0.2 M50 mL NaOH0.1 M25 mL HCl0.3M25 mL

Total Volume = (50+25+25) = 100 mL

Since NaCl is a neutral salt. So, it's concentration will not have affect on mixture.

Calculating milliequivalents (meq.) of NaOH and HCl.
meq= Normality × Volume
Normality=Molarity × n-factor
Since,
n-factor of HCl = n-factor of NaOH = 1

Normality= Molarity

meq.= Molarity × Volume
meq.NaOH=0.1×25=2.5 meq.
meq.HCl=0.3×25=7.5 meq.
[H]+=meq.HClmeq.NaOHTotal Volume=(7.52.5) meq.100 mL[H]+=0.05 N=0.05 M

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon