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Question

What will be the H+ ion concentration of a solution prepared by mixing 50 mL of 0.20 M NaCl, 25 mL of 0.10 M NaOH and 25 mL of 0.30 M HCl?

A
0.5 M
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B
0.05 M
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C
0.02 M
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D
0.10 M
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Solution

The correct option is B 0.05 M
NaCl0.2 M50 mL NaOH0.1 M25 mL HCl0.3M25 mL

Total Volume = (50+25+25) = 100 mL

Since NaCl is a neutral salt. So, it's concentration will not have affect on mixture.

Calculating milliequivalents (meq.) of NaOH and HCl.
meq= Normality × Volume
Normality=Molarity × n-factor
Since,
n-factor of HCl = n-factor of NaOH = 1

Normality= Molarity

meq.= Molarity × Volume
meq.NaOH=0.1×25=2.5 meq.
meq.HCl=0.3×25=7.5 meq.
[H]+=meq.HClmeq.NaOHTotal Volume=(7.52.5) meq.100 mL[H]+=0.05 N=0.05 M

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