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Question

What will be the HCF of (x2+x),(x+1)3 and (x3+1)?

A
(x3+1)
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B
x(x+1)3
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C
(x+1)
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D
(1+x)3
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Solution

The correct option is C (x+1)
x2+x=x(x+1)
(x+1)3=(x+1)×(x+1)×(x+1)
x3+1=(x)3+(1)3=(x+1)(x2x+1)
Required H.C.F.=(x+1).
Option C is correct.

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