Question

What will be the heat generated in a coil of resistance $50\Omega$, in joule, when a current of $6A$ flows through it for $2$ minutes?

• A. $2.16\times {10}^{5}joule$
• B. $21.6\times {10}^{5}joule$
• C. $216\times {10}^{5}joule$
• D. $0.216\times {10}^{5}joule$

Answer 1

The correct option is A $2.16\times {10}^{5}joule$

Given:

Resistance of the coil $R=50\Omega$

Current in the coil $I=6A$

Time $t=2min=120s$

From Joule's heating law we know that,

The amount of heat generated $H=I^{2}Rt$

$\therefore H=(6{)}^2\times 50\times 120=216000=2.16\times {10}^{5}joule$