What will be the height of a cuboid of volume 168 $m^{3}$ , if the area of its base is 28 $m^{2}$ ?

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Solution

Volume of a cuboid = 168 $m^{3}$
Area of its base i.e., $l \times b = 28 m^{3}$
$∴$ Height = $\frac{V o l u m e}{l \times b} = \frac{168}{28}$ = 6 m

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What will be the height of a cuboid of volume 168 m3, if the area of its base is 28 m2?

Volume of a cuboid = 168 m3 Area of its base i.e., l×b=28m3 ∴ Height = Volumel×b=16828= 6 m

What will be the height of a cuboid of volume 168 $m^{3}$ , if the area of its base is 28 $m^{2}$ ?

Volume of a cuboid = 168 $m^{3}$
Area of its base i.e., $l \times b = 28 m^{3}$
$∴$ Height = $\frac{V o l u m e}{l \times b} = \frac{168}{28}$ = 6 m