Question

What will be the height of image when an object of $2mm$ is placed at a distance $20cm$ infront of the axis of a convex mirror of radius of curvature $40cm$ ?

• A. $20mm$
• B. $10mm$
• C. $6mm$
• D. $1mm$

Answer 1

The correct option is D $1mm$

$\begin{array}{c}\frac{1}{V}+\frac{1}{\mu }=\frac{1}{f}\\ \frac{1}{V}=\frac{1}{10},V=10cm\end{array}$

Height of object

$\begin{array}{c}=2mm=\frac{1}{5}cm\\ \frac{Hi}{Ho}=\frac{V}{4}\\ \frac{Hi}{1/5}=\frac{10}{-20}\Rightarrow Hi=-\frac{1}{10}\\ 1mmaboveaxis\end{array}$