Question

What will be the ionisation energy of $B{e}^{3+}$ ion?

• A. 13.6 eV
• B. 54.4 eV
• C. 122.4 eV
• D. 217.6 eV

Answer 1

The correct option is D 217.6 eV

The energy of the first Bohr orbit of a hydrogen like atom is given as
$E_1=-13.6Z^{2}eV$
For $B{e}^{3+}$, Z = 4
$\therefore E_1=-13.6\times 16eV=217.6eV$
So if we provide 217.6 ev $B{e}^{3+}$ will ionise