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Question

What will be the Kb value of a weak base (BOH) of which a 0.1 M solution has a pH of 8, when it is half neutralized with 0.1 M HNO3?

A
108
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B
104
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C
106
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D
107
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Solution

The correct option is C 106
Ka.Kb=Kw
under this condition, pH = pKa = 8 since a buffer is formed with equal concentrations of the weak base and the salt of its conjugate acid.
Ka=108
or 108×Kb=1014Kb=106

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