What will be the Kb value of a weak base (BOH) of which a 0.1 M solution has a pH of 8, when it is half neutralized with 0.1 M HNO3?
A
10−8
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B
10−4
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C
10−6
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D
10−7
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Solution
The correct option is C10−6 Ka.Kb=Kw under this condition, pH = pKa = 8 since a buffer is formed with equal concentrations of the weak base and the salt of its conjugate acid. ⇒Ka=10−8 or 10−8×Kb=10−14⇒Kb=10−6