Question

What will be the lateral surface area of a triangular prism having an equilateral triangle with side $5$ cm as base and a height of $8$ cm?

Answer 1

For this triangular prism,
$\text{Lateral Surface Area = Perimeter of the base}\times h=(a+b+c)\times h$
where $a,b,c$ are the sides of the triangular base and $h$ is the height of the prism.

$\therefore$ Lateral Surface Area $=(5+5+5)8$
$=15\times 8=120$ cm${}^2$