What will be the length of the mercury column in a barometer tube, when the atmospheric pressure is $75$ cm of mercury and the tube is inclined at an angle of $60$ to the vertical?

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Solution

Given:
$P = 75$ cm of Hg
Pressure is develop due to vertical hight in the barometer
hence Atmospheric pressure, $P = l c o s θ = l c o s 60^{\circ} = l / 2$
$l = 2 P = 2 \times 75$ cm
$l = 150$ cm

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What will be the length of the mercury column in a barometer tube, when the atmospheric pressure is 75 cm of mercury and the tube is inclined at an angle of 60 to the vertical?

Given: P=75cm of HgPressure is develop due to vertical hight in the barometerhence Atmospheric pressure, P=lcosθ=lcos60∘=l/2 l=2P=2×75 cm l=150 cm

What will be the length of the mercury column in a barometer tube, when the atmospheric pressure is $75$ cm of mercury and the tube is inclined at an angle of $60$ to the vertical?

Given:
$P = 75$ cm of Hg
Pressure is develop due to vertical hight in the barometer
hence Atmospheric pressure, $P = l c o s θ = l c o s 60^{\circ} = l / 2$
$l = 2 P = 2 \times 75$ cm
$l = 150$ cm