Question

What will be the major product, when $2$-methyl butane undergoes bromination in presence of light?

• A. $1$-bromo-$2$-methyl butane
• B. $2$-bromo-$2$-methyl butane
• C. $2$-bromo-$3$-methyl butane
• D. $1$-bromo-$3$-methyl butane

Answer 1

The correct option is B $2$-bromo-$2$-methyl butane

In presence of sun light, free radical mechanism takes place and most stable $3^0$ free radical forms in intermediate so 2-bromo-2-methyl butane forms as major product.