What will be the molarity of a solution of $0.13$ M solution of $N a C l$ when it is diluted from $1000$ ml to $2100$ ml?

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Solution

Molarity= $\frac{W e i g h t}{G M W} \times \frac{1000}{V (m l)}$
$\Rightarrow 0.13 = \frac{W e i g h t}{58.5} \times \frac{1000}{1000}$ [When volume= $1000 m l$ ; GMW of $N a C l = 58.5 g$ ]
$\Rightarrow (0.13) (58.5)$ =Weight
$\Rightarrow W e i g h t = 7.605$

When it is diluted to $2100 m l$ , then molarity is
$\Rightarrow$ Molarity= $\frac{7.605}{58.5} \times \frac{1000}{2100}$
$= 0.006$
$∴$ Molarity when it is diluted is $0.006 m o l e s / L i t$ .

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