What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL ?

(a) $4 m o l L^{- 1}$ (b) $20 m o l L^{- 1}$

(c) $0.2 m o l L^{- 1}$ (d) $2 m o l L^{- 1}$

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Solution

Since, molarity (M) is calculated by following equation

$M o l a r i t y = \frac{w e i g h t \times 1000}{m o l e c u l a r w e i g h t \times v o l u m e (m L)}$

$= \frac{5.85 \times 1000}{58.5 \times 500} = 0.2 m o l L^{- 1}$

Note Molarity of solution depends upon temperature because volume of a solution is temperature dependent.

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