What will be the molarity of a solution, which contains 5.85 g of $N a C l (s)$ per 500 mL?

4 m o l L^{- 1}

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20 m o l L^{- 1}

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0.2 m o l L^{- 1}

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2 m o l L^{- 1}

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Solution

The correct option is B $0.2 m o l L^{- 1}$
Molarity, $M =$ number of moles/volume of solution
$M = \frac{n}{V}$
Number of moles, $n =$ mass/molar mass
Molar mass of $N a C l$ =58.5 g/mol
Mass = 5.85g
$n = 5.85 / 58.5 = 0.1$ mol
Volume, $V = 500$ mL $= 0.5$ L
$∴ M = 0.1 / 0.5 = 0.2 m o l / L$
Hence, option $C$ is correct.

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What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL ?

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